Today's issue of MIT's student newspaper, The Tech, accurately reported that we have received a record high 11,231 applications this year (this number will probably change slightly by the time we get to selection committee).
While the article (as Ben has pointed out) contains a number of factual errors, it does also correctly state that we have seen a rise in both domestic and international applicants. We have received greater than 2,500 international applications and nearly 9,000 domestic applications this year, both record highs.
It is shaping up to be an extremely competitive year for MIT admissions. Between the early and regular action applicants I've already seen, I am disappointed to know that we won't be able to find room for all of the many, many terrific applicants. But it also means that the MIT Class of 2010 will be among the best ever. I'm excited to continue selecting the class!
Comments (Closed after 30 days to reduce spam)
Posted by: Christine Li on January 18, 2006
Posted by: mohan on January 18, 2006
Okay. Wow.
I can't be the only one who looked at that number and thought, "Whoa, that's really high..."
Posted by: thekeri on January 18, 2006
Its fun to know that MIT recieved a record high 11,000 applications.
Guess what, the Indian institute of Technology, recieves a total of 125million domestic application....big number right finally they take in 5000. Ha ha...I know that is terrific. But yay! I got in...
Posted by: Arka on January 18, 2006
Okay, doesn't sound quite as right as 525,600 minutes, but it'll do for now.
Kudos to all of you for all the hard work.
Posted by: Nalin K on January 19, 2006
Posted by: Eric Asava-Aree on January 19, 2006
Posted by: 0 on January 19, 2006
the total number of applicants selected are 4000.For getting a good stream/branch you should have a rank in the top 1500, which is less than 99th percentile
Posted by: akshay on January 19, 2006
Posted by: akshay on January 19, 2006
Well but we are talking about MIT here.And this pool is really very intense.
Btw Arka how'd you get into IIT the exam is in April 2006 or did u qualify IIT 2005
"But it also means that the MIT Class of 2010 will be among the best ever."
Since I will be in it. :D
joking although I seriously hope to get through.
Posted by: shikhar on January 19, 2006
Thats what the following website says!!!!
http://www.kamalsinha.com/iit/acceptance-rate.html
Dont blame me.....
And ya! I got in the IIT 2005. But decided to get in MIT. And continue with Shikhar ""But it also means that the MIT Class of 2010 will be among the best ever.". Since all of us will be in....jk.
Have fun!
Posted by: Arka on January 19, 2006
btw, lots of indians on these message boards?
and just a note, there is an iit in america, it's called the Illinois Institute of Technology.. my cousin brother in Chicago fooled me once b/c he said he got into IIT. i was amazed and then he was like nah, it's illinois.
Posted by: Siddharth on January 19, 2006
Posted by: Rafael on January 19, 2006
Something I read on an internet site really shocked me. The article said that an admissions officer will stop reading the essay and deny admission to the student just because of a typing mistake. Is that really true? Isn't it unfair to international students, who might make a grammar or awkward word usage mistake because they are not native speakers?
Posted by: moonghostv on January 19, 2006
and regarding your question about typing mistakes: I can't really believe that and it would very much surprise me if there was such a policy in place.
Posted by: Dinyar on January 19, 2006
I am taking my JEE this year. Its challenging but I want to enjoy it. JEE had been changed this year I am sure that the competitors will be more than 3,00,000. But I want to be in the top of the race.
Niti sharma(MIT class of 2005)had achieved rank around 900 in JEE.
Posted by: Mohan on January 19, 2006
Posted by: Mohan on January 19, 2006
That leaves 1123 seats open to be given among 11,231 candidates. That's about 10.00% admission rate - lower than Princeton, Harvard, and about the same as Yale.
Of course, this number will probably increase after incomplete applications are removed and EA students decline their seats.
Posted by: Alexandre on January 19, 2006
Domestic: 1033 seats among nearly 9000 applicants (11.5%)
International: 90 seats among over 2500 applicants (3.6%)
Posted by: Alexandre on January 19, 2006
Posted by: angelina on January 19, 2006
Does anyone of you use any IMs? It would be nice to meet some of the prospective students, exchange opinions, experiences etc
Maciek, Poland
Posted by: Maciek on January 19, 2006
Posted by: Maciek on January 19, 2006
Does this mean the waiting list will have a record size?
Posted by: Chandresh on January 19, 2006
Only on an MIT forum would the attention to numbers and odds be so high
Posted by: Drew on January 19, 2006
I have a question. Seeing as the number of applicants that have applied this year are up 7.5% from last year does this mean that you might be planning to increase the number of those admitted (Hopefully)? I was just wondering.
Posted by: Fadl on January 19, 2006
I applied Early Action and was also bogged down by the numbers and really nervous when I read that MIT has the lowest Early Action acceptance rate at 12%, whereas early at Harvard, Yale, Princeton are all closer to 20%.
However, don't let the numbers get to you! I got in early action...so just wait and see! You too could be part of the 10, 11, or 12% that get in regular action!!!
Good luck everyone and relax...there's nothing you can do about the application right now. Just wait, hope, and you'll see!
Posted by: julia on January 19, 2006
Posted by: 0 on January 19, 2006
Ok, now it is very clear for me that international application to MIT is very very very very very very very very competitive, only 3.6%!!!!!!!!!. I am so anxious and nervous, I guess most of you are having the same feelings. We have to wait until mid-march to know the decision. Good luck to everyone!
Juan Jhong C
Posted by: Juan Jhong Chung on January 19, 2006
Ok, now it is very clear for me that international application to MIT is very very very very very very very very competitive, only 3.6%!!!!!!!!!. I am so nervous, I guess most of you are having the same feeling. We have to wait until mid-march to know the decision. By that time, anxiety might have already kill me.
Good luck to everyone!
Juan Jhong Chung
Posted by: Juan Jhong Chung on January 19, 2006
Posted by: Juan Jhong Chung on January 19, 2006
I am so excited already.
I'll see you soon =D
Posted by: LongL on January 19, 2006
From ur link, "IIT JEE is taken mostly by middle class applicants from urban areas with total population about 125 million"
im guessing this to mean that the URBAN AREAS have total pop of ~125mil, not that the actual number of applicants is 125 million.
just a thought. enjoy!
Posted by: Siddharth on January 19, 2006
Or might be "reading data eroor"
But finally it was an "execution error"
I need to reinstall 'my' Operating System.
I mean "MY" and not my computers.
Before getting into MIT ~_^
Guys lets forget about IIT and think about MIT.
Waiting to get the....
System.out.println("You are accepted to MIT");
ha ha ,
Fun
Posted by: Arka on January 19, 2006
Posted by: Arka on January 19, 2006
run /Users/johnderrico/Documents/Files/work in progress/fminsearchbnd2.m
run /Users/johnderrico/Documents/Files/work in progress/fminsearchbndx.m
run /Users/johnderrico/Desktop/My_FEX/fminsearchbnd.m
run /Users/johnderrico/Desktop/My_FEX/opt_reg_tips/fminsearchbnd.m
run /Applications/MATLAB701/toolbox/matlab/funfun/fminsearch.m
You will find links in your command window, allowing you to run or edit any of
the functions it finds with no more than a mouse click. Try whichx. I predict you
will find it useful
They are really very useful.
Posted by: Arka on January 19, 2006
Ha ha ...I feel like a detective
Posted by: Arka on January 19, 2006
10,443 students applied
1,495 admitted
2794 students applied early action
384 students admitted early
2240 students deferred to regular action
267 deferred applicants admitted during regular action
2210 international students applied
112 admitted
From what I can gather, if 8% of the admits can be Intl then they could have accepted 119 students but they accepted 112 meaning that only 7.55% of the admits were Intl. This made the acceptance rate of Intl students 5.06%.
For EA students, if you count those that were actually admitted EA and those that were admitted RA the actual acceptance rate for those who applied EA was 23.3%. This means that 43.54% of the total admits were EA applicants.
48.9% of the admits were composed of RA students meaning that there is actually an acceptance rate of 13.46% if you apply RA.
On a last note, 25.68% of the admits were admitted during EA.
Posted by: R on January 19, 2006
Posted by: Steven Lu on January 20, 2006
1. IITJEE is given by approx. 250,000 students. The top 2500-3000 get into IIT's while the rest get into ISM Dhanbad and BHU-IT. To get a seat in Electrical, Software, Mechanical, Communications and Electronics or other so-called "In-Demand" Courses, you have to get a top 1000 rank.
2.The entrance exam is undoubtedly the toughest in the world, but if you're concepts are clear, it's not so much of a problem.
3. Arka, you claim in your web-page to be in 11th standard. Unless that's 3 years old, you could not have possibly cleared JEE 2005.
4. And don't think we're idiots, if u got through IIT, you cannot be so crazy as to give up that seat to take a year off and apply to MIT.
5. And finally, India is a very vastly populated country, but even we do not have an urban population of 125 million! Allow me to qoute Max Mueller, "India's heart lives and grows in it's villages".
6. And now, back to MIT!
If the selection rate is 3.6%, those students getting in must be extraordinary geniuses. To qoute another great modern philosopher, Homer Simpson, "But I'm not a genius....or are I?"
Posted by: Harish on January 20, 2006
Guess what.....how many years old do you think my website to be....any guesses....
And I have been to MIT on visits and thats why I am crazy to get in MIT.....I have my brother in IIT. So why not me be in somewhere in the MIT. Afterall I love that institute.....It depends on taste you know.....if u understand.
Posted by: Arka on January 20, 2006
Guess what.....how many years old do you think my website to be....any guesses....And how can you even think of me applying to MIT when I am in the 11th grade. Comon Harish....we need some sense here.
And I have been to MIT on a small visits and thats why I am crazy to get in MIT.....I have my brother in IIT. So why not me be in somewhere in the MIT. Afterall I love that institute.....It depends on taste you know.....if u understand.
Posted by: Arka on January 20, 2006
Posted by: Victoria on January 20, 2006
Arka, I think, did not fool any one b'cause even when a student is selected to IIT he may give up his/her seat when one think that he/she might want a better seat and will reappear for the test for second time. It's the case with my cousin at first attempt he recieved around 1700 so he took a chance and reappeared attaining a rank around 400. Then it is obvious with any one who know MIT and its greatness would take a chance of letting the IIT seat away.
Posted by: ramya on January 20, 2006
I accept it many of the students have the courage to do it but most take admission and reappear
I hope either one who is sure of getting into MIT or someone like me who could not take admission despite ranking 14 due to surgery only will leave
well may be ARKA is a lot of genious and may get but Iam not sure for MIT
Posted by: ANONYMOUS on January 20, 2006
i hope the author have wrongly use 125 million in place of thousand.
As far as i know 125000 to 150000 students apply aproximately and moreover I dont agree about the quality of education imparted by IIT (as mentioned in the article)
They are somewhere near the top .
Posted by: ANONYMOUS on January 20, 2006
Posted by: Ramya on January 20, 2006
In the above link one can find the rankings of all the top 500 universities in the world
Posted by: Ramya on January 20, 2006
......please answer the questions of prospectives, Please.......
Posted by: 0 on January 20, 2006
......please answer the questions of prospectives, Please.......
Posted by: 0 on January 20, 2006
Posted by: Jason on January 20, 2006
total admissions (approx): 1500 => 120 internationals
early admission: 377
regular admission: 1123 admissions | 9000 applicants => 12,4%
international students: 120 admissions | 2500 applicants => 4,8%
I didn't mean to be the wise guy, but the geek wanted out. :]
Posted by: Julius P. on January 20, 2006
Posted by: jian on January 20, 2006
The system of rankings like the one provided Institute of Higher Education, Shanghai Jiao Tong University may not necessarily be correct.
As far as your point about research is concerned, in India there are quite a few problems assosiated with funding thus the research funds are quite low.Even with these low funds the students manage to carry out valuable research, which is quite creditable. Also IIT has been producing excellent engineers which do very well in the industry.You cannot judge a university only on the basis of the amount of research it has conducted.If there is a single reason why IIT doesn't invest much money into research, its because it doesnt have much.
Posted by: Anonymous on January 20, 2006
Posted by: Chandresh on January 20, 2006
Posted by: abstract on January 20, 2006
Posted by: MJ Kamalov on January 20, 2006
Best of luck to you!
Posted by: Dinyar on January 20, 2006
Posted by: Eric Asava-Aree on January 21, 2006
Posted by: akshay on January 21, 2006
I have heard various comments on the quota of int'l students taken by MIT. In the other blog, a percentage of 8% was given, which comes around to be roughly 115 students. Does anyone have any idea how many exactly will be taken?any quotas for individual countries?
Posted by: 0 on January 21, 2006
Posted by: ODHIAMBO on January 21, 2006
Posted by: ODHIAMBO on January 21, 2006
Below Facts are from it.
1)International admission to MIT is very competitive. In 2005,112 international students were admitted from a pool of 2,210 applcants.
2)Almost all international applicants who are admitted to MIT have earned some form of regional,national or international distinctions in areas as diverse as leadership, music, art, scientific research, acdemic competition or athletics.
P.S: An apple tree in MIT's alumni garden is a direct descendent of the one Sir Isaac Newton was reportedly sitting when he conceived the theory of gravity.
Posted by: Mohan on January 21, 2006
Posted by: Rafael on January 21, 2006
Posted by: Nicolas Papamichael on January 21, 2006
I am an international applicant and I have mediocre CR and Wr scores on the SAT 1. I have attented a Greek public (government) school in Cyprus teaching us English only 1 1/2 hours a week. Will this be taken into account when reviewing my app? When scores are sent from the college board to MIT are the percentiles and actual raw marks shown?
Thanks!
ps. Sorry I've also posted this one on the wrong forum (The Coin is Found) by mistake
Posted by: Nicolas Papamichael on January 21, 2006
"We are sorry to inform you..." OR "Congratulation! You have been...."
A curious question: what other universities have you applied?
Again GOOD LUCK TO EVERY BODY!
Posted by: Juan Jhong Chung on January 21, 2006
good luck pples!
Posted by: April (no longer waiting but deferred) on January 21, 2006
Good luck Mr. McGann.
Posted by: Robert on January 21, 2006
Good luck Mr. McGann.
Posted by: Robert on January 21, 2006
ok, kidding, but who knows? ;-p
Posted by: jian on January 22, 2006
So please, let us try to overcome this initial challenge of our inherited fear to fail and accept / believe what the admissions office has received.
Good luck to every body and best regards from Uganda, East Africa where we seem to have only a single MIT alumni and non in Uganda.
"could the first be this author?"
Alex Myne Kirungi
Posted by: Alex Myne Kirungi on January 22, 2006
Posted by: Rafael on January 22, 2006
I am an international applicant
I applied only to MIT, PRINCETON AND HARVARD.
Juan Jhong Chung: where else did you apply?
Posted by: mohan on January 22, 2006
Posted by: usha on January 22, 2006
Posted by: uren on January 22, 2006
Posted by: Mushal on January 22, 2006
I just had a quick question. Is it true that having references from well known people or MIT Alumnis act as an advantage to your admissions?
Posted by: 0 on January 22, 2006
Posted by: 0 on January 22, 2006
2 University of California, Berkeley US
3 Indian Institutes of Technology India
4 Stanford University US
5 Imperial College London UK
6 Cambridge University UK
7 California Institute of Technology US
8 Tokyo University Japan
9 National University of Singapore Singapore
10 Beijing University China
11 Tokyo Institute of Technology Japan
12 ETH Zurich Switzerland
13 Oxford University UK
14 Carnegie Mellon University US
15 Delft University of Technology Netherlands
16 New South Wales University Australia
17 Tsing Hua University China
18 Melbourne University Australia
19 Kyoto University Japan
20 Georgia Institute of Technology US
21 Harvard University US
22 Ecole Polytechnique France
23 Hong Kong University Sci & Technol HongKong
24 Monash University Australia
25 Technion Israel Inst of Technol Israel
26 Nanyang Technological University Singapore
27 Illinois University US
28 Aachen RWTH Germany
29 Australian National University Australia
30 University of Texas at Austin US
31 University of Toronto Canada
32 Vienna University of Technology Austria
33 Technical University Munich Germany
34 Cornell University US
35 Purdue University US
36 University of California, Los Angeles US
36 Ecole Poly F
Posted by: 0 on January 22, 2006
Posted by: 0 on January 22, 2006
Posted by: Alissa on January 22, 2006
If you need something to take your mind off the stress of waiting for the admission decision, check out Sky Monsters, on the National Geographic channel tonight at 9. It
Posted by: Daniela Buchman on January 22, 2006
This is my own ranking:
MIT
Caltech
Harvard
Princeton
Stanford
Yale
Good luck!
Posted by: Juan Jhong Chung on January 22, 2006
That has got me worried a little bit.
But oh well, I guess I will just have to wait and see..
and yes, there are a lot of Indians on this blog!
Posted by: akhil on January 22, 2006
I encourage you to have fun! There is no point at this time to think about the application. All parts, recommendations and transcripts have already been sent. I know that waiting is very painful to all of us but we can make it a little more relaxing.
This is the time of the year that we should be spending with our little brothers or sisters, with our parents and with our friends. Believe it or not, you are going to miss them more than you think. For most of us, these are going to be the last months in our homes. Soon there won't be anymore mom's charms or dad's advice and even though cell phones and internet make distance shorter, feelings and emotions cannot be translated to data language to send them in an email or through a phone call.
The adventure of going to college is the most exciting in our life. It is a new beginning with new friends and new challenges. It is the beginning of our dream, of what we want to do in our future. In this difficult path we are going to learn not only math but also how the real life is. Be ready!
I am so happy to share my experiences and worries with many prospective students around the world. Since I met you, I am not afraid any more about the future of the world society because I know that with people like you the world's destiny is going to change. We are the best example that no matter where we are from or what language do we speak, our minds think in the same way. All of us want the best for the world.
I am sure you are the best students in the world, and that is why you are applying to the best college. Everyone is so special and we should not doubt it. We should never be afraid to show our knowledge. Have faith on ourselves and I am sure we will success wherever we go.
Good luck to everybody
Posted by: Juan Jhong Chung on January 22, 2006
I just had a quick question. Is it true that having references from well known people or MIT Alumnis act as an advantage to your admissions?
Posted by: Anonymous on January 22, 2006 10:46 AM
No, according to numerous admissions officers.
It has to be a good reference, never mind from where. Although I don't recommend convicted serial killers.
these are top 60 technical universities in the world
Where'd you get that? Stanford ranked higher than Caltech?
And finally,
eeeek!....(gag)...thud. I agree totally.
Posted by: Victoria on January 22, 2006
Posted by: Cool guy on January 22, 2006
I would be both honored and amazed if I acually make MIT, but at the same time I know I will what I do regardless.
Remember, it's the people that make the school not vice versa.
Good luck to everyone in the RA pool. I hope everyone who deserves to get in makes it.
Posted by: Sam T on January 22, 2006
Posted by: Sam T on January 22, 2006
Posted by: Frank on January 22, 2006
Posted by: Scary on January 22, 2006
IIT has given by 'anonymous' stands 3rd in the world. Hence, It is obvious for any Indian student to have ambition to get in to IIT. But in present days this criteria of students has became as a source for earning from book sellers to the lecturers. I am really speaking that there are nearly "hundred" coaching centers for IIT-JEE in our area in 5 km radius. To get in to these coaching centres you should take a entrance test which will be challenging than IIT for the students at that level of 10th standard. Do you know! for taking these entrance tests there will be again coaching centers (which will start from 6th grade). For getting in some of these coaching centers you should take the entrance test.
In this way a student's major(because engineering and science are the only majors at IIT's)is been deciding in that small age of 5th class.
With all these effort there is no guarantee that a student will enter in to IIT (because there are only 2500-3000)and our nation is loosing the brilliant students who would have glow bright if they taken ARTS or the subject which they like. (You know! a student in india who taken his major as arts is considered mere fool( as there are very less payments for the jobs which can be earned by these majors) or not an intelligent.)In the mindset of a parent they always think that their child should become a doctor or a engineer.
Now UREN how many years a student is preparing for IIT! (nearly 7 years)
Posted by: 0 on January 22, 2006
Posted by: 0 on January 22, 2006
Posted by: 0 on January 22, 2006
But my cousin who studied "Masters of Museology"(predominantly an arts subject), with historical anthropology as major...got a job in the "Central Government" with a starting income of Rs.35000.....~_^...So what do you say about that. All of us dont consider "Arts students as fools in India". Nevertheless in the place I am from...Guwahati.(Assam)Most of them become leaders in their fields in India and abroad with majoring in the Arts stream.
And regarding the IIT thing...I strpngly aggree that the entrance coaching is nowadays becoming a kind of business, and I guess IITs step in changing the pattern must have had an declining affect.
Cheers!
Posted by: Arka on January 22, 2006
Cheers!
Posted by: Arka on January 22, 2006
Posted by: 0 on January 22, 2006
Posted by: 0 on January 23, 2006
Posted by: Rohit Nair on January 23, 2006
and ramya posted http://ed.sjtu.edu.cn/ranking.htm
, both seemingly quite different.
Rating a university is of no use, its ultimately which one uits you. Not all great mans have been a MIT or IIT alum. Most of them belonged to schools no body ever knew(i hope i stole this sentence from somewhere)
so let us put an end to this discussion
good luck to all with all your applications
Posted by: ANONYMOUS on January 23, 2006
This link does not works above
Posted by: ANONYMOUS on January 23, 2006
Quetion from permutations and combinations.
How many ways can the faces of cube can be coloured with 6 different colours??
Posted by: 0 on January 23, 2006
Quetion from permutations and combinations.
How many ways can the faces of cube can be coloured with 6 different colours?
Posted by: s(Q & A) on January 23, 2006
Posted by: uren on January 23, 2006
720 ways of colouring the cube?
Posted by: Rohit Nair on January 23, 2006
Will this influence my admission somehow? :D
Posted by: Rohit Nair on January 23, 2006
2 opposite to 5
3 to 4
considering 1 and 6 as top bottom (or bottom top)
they can be painted in 6*5 ways
For the four sides no. of arrangements possible for four colurs= (4-1)!=6
so total no of aarrangement = 30*6=180
AM I CORRECT??
was it a similar problem or same whose answer was one
am confused??
Posted by: Vivek on January 23, 2006
Posted by: s(Q & A) on January 23, 2006
We have six colours, and six faces. I can put the first colour in any one of six positions, after which there will be five positions left. Now I have five places in which to put the second colour, and so, so far, there are a total of 6x5 ways of placing two colours onto a cube. Proceeding in this manner, the total number of possible combinations should be
6x5x4x3x2x1 = 6! = 720
Posted by: Rohit Nair on January 23, 2006
Posted by: Rohit Nair on January 23, 2006
Posted by: M on January 23, 2006
Posted by: M on January 23, 2006
Hoping every one had taken high school maths and a problem for maths L II C and know all the terms on the common scientific calculator.
If the function f(X)= X^3-9X^2+24X+c has three real and distinct roots a,b,c then the value of
[a]++[c],where [.]denotes the greatest integer function, is
A) 8,when c belongs to (-18,-16)
B) 8,when c belongs to (-16,-14)
c) 8,when c belongs to (-20,-18)
d) none of these
***this problem can be solved in 2-3 minutes***
Posted by: Just for a change to S (Q & A) on January 23, 2006
f(X)= X^3-9X^2+24X+c
Posted by: 0 on January 23, 2006
Btw Matt hows the application reading going.. I am waiting for your omnibus patiently.
Posted by: shikhar on January 23, 2006
Always put Number 1 towards the table that we can not see it then
There arises two cases
a) Now first we should consider that 3 on the top (up ward) that we can see. Always one can see a face towards him. Number it as 2. Then there remains three faces which can be numbered in 3.2.1 = 6 ways.
b) In next case if number 3 is not on the top then it can be seen on the sides (as 1 is fixed)
Now we can number remaining four faces in 4.3.2.1 = 24 ways.
Posted by: M on January 23, 2006
Posted by: M on January 23, 2006
Posted by: M on January 23, 2006
Anybody here who's a graphic designer, by any chance? Does anyone know if there's a graphic designing club at MIT?
Posted by: Rohit Nair on January 23, 2006
This thread has now 104 posts the "THIRD" highest among all blogs. Yay!!!
Come on we need to make it the highest of all.....
Go......
I had a electricity related question.....
We know two equipotential surfaces can never have a single common area. We know one reason...we will have two Electric field vector at the same point, in the IPhO prelims we were asked to put out another reason...any answers.
Have fun!
Posted by: Arka on January 23, 2006
Posted by: Rohit Nair on January 23, 2006
Posted by: Rohit Nair on January 23, 2006
Posted by: Benjamin Prosnitz on January 23, 2006
MIT
PRINCETON
HARVARD
IIT (Indian institute of technology)India
Posted by: Mohan on January 23, 2006
Posted by: Mohan on January 23, 2006
Posted by: 0 on January 23, 2006
Posted by: Mohan on January 23, 2006
Posted by: Juan Jhong Chung on January 23, 2006
Mat i have a question; if your an American who lives outside the US and you school does not follow the US school system do you need to hand in a Mid-Year Report or some sort of supplement for it?
Posted by: 0 on January 23, 2006
Posted by: April (no longer waiting but deferred) on January 23, 2006
Posted by: April (no longer waiting but deferred) on January 23, 2006
Posted by: April (no longer waiting but deferred) on January 23, 2006
Posted by: April (no longer waiting but deferred) on January 23, 2006
Each color can be used more than once, remember that =)
123456=different colors
1,1,1,1,1,1
1,1,1,1,1,2
1,1,1,1,1,3
1,1,1,1,1,4
1,1,1,1,1,5
1,1,1,1,1,6
1,1,1,1,2,1
etc
However, some cubes will look identical, even though the colors aren't on the same exact sides. (for example, 1,1,2,1,1,1 looks identical to 2,1,1,1,1,1)
Posted by: Adam on January 23, 2006
Posted by: Adam on January 23, 2006
Posted by: 0 on January 23, 2006
Posted by: 0 on January 23, 2006
Posted by: 0 on January 23, 2006
I have been analizyng Benjamin Prosnitz's answer: "Vivek's answer to the cube problem includes duplicates. I am pretty sure that the answer is 30 ... 5 possibilities for the color of the side opposite to the initial side times 6 possibilities for the middle faces (I believe this elimintates all of the duplicates when rotating)"
If he takes out one color for the opposite faces to avoid duplicates, he is missing the posibilities when all faces have the same color. When all faces have the same color, each face has 6 posibilities. His solution does not work for all cases.
The solution presented by Adam and I is the maximun number of ways of painting a cube. Now think again that a number represents a color, so:
the cube 1,1,1,1,1,2 is identical to 1,1,1,1,2,1 ; 1,1,1,2,1,1 ; 1,1,2,1,1,1 ; 1,2,1,1,1,1 ; 2,1,1,1,1,1. So every 6 ways are the same.... the answer is 6^5= 7776
Posted by: Juan Jhong Chung on January 23, 2006
Anyways!!!
We have been posting the most and its now the highest of all blogs! Yes!!!!
Cheers
Posted by: Arka on January 23, 2006
Posted by: Juan Jhong Chung on January 23, 2006
Posted by: Adam on January 23, 2006
Always put Number 1 towards the table that we can not see it then
There arises two cases
a) Now first we should consider that 3 on the top (up ward) that we can see. Always one can see a face towards him. Number it as 2. Then there remains three faces which can be numbered in 3.2.1 = 6 ways.
b) In next case if number 3 is not on the top then it can be seen on the sides (as 1 is fixed)
Now we can number remaining four faces in 4.3.2.1 = 24 ways.
24+6=30
It may be true
Posted by: Mohan on January 23, 2006
How many ways can the faces of cube can be coloured with 6 different colours and one colour to each Face? Now it is clear from ambiguty!!!
Posted by: Correction on January 23, 2006
Take a circle, divide into eighths. You may use 4 colors to color the segments. Colors may be repeated as long as you use all 4 colors at least once. What are the total combinations possible?
Posted by: s(Q & A) on January 23, 2006
I for one need all the brownie points I can get lol.
BTW, I heard that there is one fraternity at MIT that has ridiculously hot guys. Forgive me for being a girl, but I would like to know which one that is
Posted by: Minh Ngoc Nguyen on January 24, 2006
Conservatives in Canada just won a minority government. Usher in the end of liberalism and the start of conservatism.
----------------
Okay, enough detracting from me. Haha... Let's focus on our feelings here. Who's really *that* nervous about the admission decisions?
Posted by: Eric Asava-Aree on January 24, 2006
And, if anyone here is getting bored of all the nerd stuff, visit my website. :D
http://www.the-paragon.net
Posted by: Rohit Nair on January 24, 2006
We have to take at least 4 different colours. So first fill any 4 of the 8 sectors in 8P4(=1680) ways. This will have to be multiplied in all the cases.
Now, the different cases that arise will be:
Case I):
The remaining 4 sectors are filled by the same colour(i.e., take any one of the four groups from red,red,red,red or green,green,green,green or etc...)
No. of ways of doing this = 4C1*(4!/4!)= 4C1 =4
Case II):
remaining four sectors are filled by 3id.(4 groups) and 1 difft.(3 groups) colours.
No. of ways = 4C1*3C1*(4!/3!)= 4*3*4 = 48
Case III):
2id. and 2id. colours (4 goups)
No. of ways = 4C2*(4!/2!2!) = 5*6 = 30
Case IV):
2id.(4 groups) and 2 difft.(3 groups) colours
No. of ways = 4C1*3C2*(4!/2!) = 4*3*6 = 48
Case V):
All 4 difft colours
No. of ways = 4! = 24
Therefore, total no. of ways = 1680*(24+48+30+48+4) = 1680*154 = 258720
That's quite huge!
Hey, if anyone can spot a glitch in the mess I just created please tell me.
PS: Is there a shorter way of doing this?
Posted by: 0 on January 24, 2006
We have to take at least 4 different colours. So first fill any 4 of the 8 sectors in 8P4(=1680) ways. This will have to be multiplied in all the cases.
Now, the different cases that arise will be:
Case I):
The remaining 4 sectors are filled by the same colour(i.e., take any one of the four groups from red,red,red,red or green,green,green,green or etc...)
No. of ways of doing this = 4C1*(4!/4!)= 4C1 =4
Case II):
remaining four sectors are filled by 3id.(4 groups) and 1 difft.(3 groups) colours.
No. of ways = 4C1*3C1*(4!/3!)= 4*3*4 = 48
Case III):
2id. and 2id. colours (4 goups)
No. of ways = 4C2*(4!/2!2!) = 5*6 = 30
Case IV):
2id.(4 groups) and 2 difft.(3 groups) colours
No. of ways = 4C1*3C2*(4!/2!) = 4*3*6 = 48
Case V):
All 4 difft colours
No. of ways = 4! = 24
Therefore, total no. of ways = 1680*(24+48+30+48+4) = 1680*154 = 258720
That's quite huge!
Hey, if anyone can spot a glitch in the mess I just created please tell me.
PS: Is there a shorter way of doing this?
Posted by: Sid on January 24, 2006
Posted by: 0 on January 24, 2006
Posted by: Sid on January 24, 2006
Did you TYPE all that? :o
I don't think the solution's that complex or huge. :p That's a lot of ASCII wasted D:
Posted by: Rohit Nair on January 24, 2006
First you select all the colours you need , and THEN arrange it in accordance with circular permutation. So:
Case I):
4 difft (which will be present in every case) and 4 id
No. of ways of selecting = 4C4*4C1
Now arrange it in 4C4*4C1*(8-1)!/4!
All cases will change likewise and the sum of all the cases will give the final answer.
If anyone can come up with a shorter answer, PLEASE post it.
Posted by: Sid on January 24, 2006
How many ways can the faces of cube can be coloured with 6 different colours and one colour to each Face? Now it is clear from ambiguty!!!"
Well, if that is the real question the answer is 1. We have 6 colors for each face, that means 6 possiblities. However it is enough if we put a different color to each face because when we rotate it, in all the ways a cube can be rotated, all faces would have had all colors.
Posted by: Juan Jhong Chung on January 24, 2006
Also, only one person has tried to answer my question, so I'm going to repost it here:
A cube is hanging from one of its vertices. A plane parallel to the ground divides the cube in two congruent polyhedra. What type of polyhedra are these? (Be specific.)
Posted by: 0 on January 24, 2006
Posted by: disgusted on January 24, 2006
Posted by: disgusted on January 24, 2006
Posted by: Andrew on January 24, 2006
Since many people are not so happy that we start a "math forum", here is my e-mail: gnohjnauj@hotmail.com . Anyone can add me to his or her contact list to have a nice chat about any topic!
Posted by: Juan Jhong Chung on January 24, 2006
Posted by: Rose on January 24, 2006
Posted by: 0 on January 24, 2006
Posted by: JOY on January 24, 2006
Posted by: disgusted on January 24, 2006
Posted by: 0 on January 24, 2006
What the wrong in it!!
You can post U R Question to Matt
Posted by: JOY on January 24, 2006
What the wrong in it!!
You can post U R Question to Matt
Posted by: JOY on January 24, 2006
Call 1 the top face and 6 the bottom face. Also, call 2 the back face. This fixes the cube to prevent repeats from rotation. There are 3x2x1 = 6 ways to arrange the remaining 3, 4, and 5.
So for the case where 1 and 6 are on opposite faces, there are 6 unique arrangements of the four remaining colors.
Now for the case where 1 and 6 are on adjacent faces, just swap 6 in for 2, 3, 4, or 5 in every possibility. That's 6 possibilities and 4 numbers to swap with in each possibility, for a total of 6x4 = 24 unique arrangements.
That gives a total of 30 unique arrangements. All other arrangements would be some other rotation of those.
Note that swapping the 1 and 6 does nothing, because they're still opposite each other after the swap.
Here's another way to think about it... start with 1 and 6 opposite for 6 possibilities. Now take 1 and 2 opposite, 1 and 3 opposite, etc. There are 5 numbers that can be opposite 1, 6 possibilites each. 5x6 = 30.
Well, it's getting late (but not 3AM, it's not THAT late where I am), so I might've missed something, but those're my thoughts.
On the hanging cube, would it be a 7-faced polyhedron? (Septahedron?) Drawing a cube from the top, I get a regular hexagonal base connected to three small isoceles triangles and three large isoceles pentagons.
Now for something completely different. To disguste... Considering MIT's size, I'm sure you'll find all sorts of people, not just math freaks like us. =P I have some friends applying to MIT for its business program, believe it or not. If MIT's not for you, then it's not.
And like Juan Chong Chung said, don't sweat it! This probably sounds super-cliched, but where you go doesn't matter as much as what you do there. Judging by what Matt and Ben have been saying, every one of us can probably be successful wherever we go. So here's to a wonderful finish to our senior years!
Posted by: Eric on January 25, 2006
Posted by: 0 on January 25, 2006
Posted by: 0 on January 25, 2006
A lot of flooding and trolling here... Between those trying to resolve math problems and those trying to beat a new record for the more messages in a single thread, the situation is quite disturbing.
Joy posted this:
_______________
What !! I am unable to understand you? some one had posted a Q which is of curiosity and critical thinking. Hence the guys are trying it!!!
What the wrong in it!
_______________
It's common sense. The aim of the comments of this article was to discuss about the topic Matt talked about. And that is definitely all. Discussing math problems on an MIT website is something understandable (and arguably). After all, this subject will be a part of students' life for all the admitted ones next year. However, this is just not the point. I wouldn
Posted by: S on January 25, 2006
____
| |
| 2 | The side faces: (6c2)/2 combo's.
____|____|____ The middle column: 4 combo's
| | | | Therefore: 2*(6c2) = 30
| 1 | 3 | 6 |
|____|____|____|
| |
| 4 |
|____|
| |
| 5 |
|____|
Posted by: Joe on January 25, 2006
Posted by: Joe on January 25, 2006
Answer: because it means ur not ALL indian!
juuuuuust kidding
and a/b u cube-problem guys, by now u couldve just bought a bunch of cubes and a couple of water colors and figured it out empirically :D
one calculus test question last year wanted to find the sides of a box to maximize volume. for some reason it was really hard for me and apparently everyone else in the class. it had some twist to it, but i forget what it was. the whole test was calculator off, so i picked pretty round numbers and ended up w/ the right answer :D i pulled 3 numbers out of the air and they were all the right answers. what was the probability of that? why, 1/(infinity)^3, of course. now how's THAT for a probability problem! just felt like bragging, and u guys WERE talking a/b cubes... ;D
and btw, Minh Ngoc Nguyen, the frat ur looking for is whichever one i join at mit... b/c u KNOW im getting in
(we really need a thumbs-up symbol)
peace in the middle east (keep dreaming, buddy!),
Siddharth Shah
Posted by: Siddharth on January 25, 2006
Posted by: Siddharth on January 25, 2006
sorry for triple-post :(
Posted by: Siddharth on January 25, 2006
I analized the possibilities by opposite pairs of faces. For the first pair, it really does not matter the order because I can rotate the cube and I will have the same (opposite sides painted as red and blue is the same as blue and red), so I have 6C2 possibilities for the first opposite pair, wich is 15.
Now for the second pair I have left 4 colors, and it also does not matter the order beause I can rotate the cube again to obtain the same. So for the second pair I have 4C2 possibilities for the second opposite pair, wich is 6.
The last pair of faces took me much more time, becuase in the last pair I believe that the position of the opposite colors does make different cubes, since I have the other for sides already painted. So for the last opposite pair I have two possibilities (2P2).
Finally, 15(the first pair)*6(the second pair)*2(the last pair)= 180 possibilities.
Maybe I am wrong and I just can
Posted by: Luiz on January 25, 2006
begin{unrelatedstuff}
1 + x + x^2 + ... + x^n = (1 - x^(n+1))/(1 - x)
end{unrelatedstuff}
Posted by: 0 on January 25, 2006
i say we stick w/ html if we're going for this tagging deal... as in unrelated stuff goes here
or, b/c this forum allows for the 128-bit deal (or is it 64? i cant remember which one it is right now... prolly 64), we can use special characters like
Posted by: Siddharth on January 25, 2006
Posted by: usha on January 31, 2006
Add a comment
Comments have been closed.