Blog
/ Academics & Research
Lessons from Loomis and Whitney a math month post

: Yes. For every point in $\pi_x(A)$, we can draw the corresponding line ... (|\pi_{xy}(A)| \cdot |\pi_{yz}(A)|\cdot |\pi_{xz}(A)|)^{\alpha}\] for some ... -dimensional case. So, for now, supposing that such a bound holds, let's figure






